In the figure, m∠1=(2x+40)° and m∠8=(12x−20)° . PLEASE IM BEGGING FOR HELP For what value of x is m∥n ?

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x =

  x = 6

Step-by-step explanation:

Angles 1 and 8 are alternate exterior angles, so they are equal.

So you can create an equation to solve for x

12x−20 = 2x+40  Subtract 2x from both sides. Add 20 to both sides

10x = 60

x = 6

If you need the  m∠1, Substitute 6 for x.  (2x+40)°  2(6) +40= 12+40 m∠1= 52°

m∠8=(12x−20)°   12(6) - 20 = 72-20  m∠8 = 52°

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

b

step-by-step explanation: