Total solar eclipses occur on a regular and predictable basis. One that could be viewed in parts of the United States occurred on March 7, 1970. The saros cycle is a period of 18 years, 11 1 3 days, and solar eclipses occur according to this cycle. For the purposes of this exercise, we ignore leap years and assume that a year is exactly 365 days. Because the saros cycle is not a whole number of days, but instead is one-third of a day longer than a day, at the end of the saros cycle, Earth will have rotated one-third revolution beyond its location at the beginning of the cycle. Thus, if a solar eclipse is viewable at a certain location, the next solar eclipse will not be. How long after March 7, 1970, will a solar eclipse again be viewable from the United States?

Step-by-step explanation:

The previous solar eclipse occured on March 7 , 1970 .

saros cycle has duration of 18 years , 11 + 1/3 days

So the earth goes 1 / 3 of its daily rotation beyond its previous location in the next solar eclipse on the earth . In order that we get solar eclipse on the same point on the earth , we shall have to wait for third solar eclipse

So total period of wait = 18 x 3 years + 11 x 3 + 1 = 54 years and 34 days

Date of next solar eclipse on the same spot = 1970 + 54 = 2024

7 th March + 34 days = April 10

likely date = April 10 , 2024 .

idk

step-by-step explanation: i just don't

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.