Two points, L and N are 160 m apart. M lies on the straight line joining L and N. An object travels from L to M at an average speed of 10 m/s in 6 seconds and then from M to N at an average speed of 25 m/s. Find the average speed of the object for it's entire journey from L to N.

Step-by-step explanation:

If the object travels from L to M at an average speed of 10 m/s in 6 seconds, we can get the distance LM using the formula;

Speed = Distance/Time

Distance = Speed * Time

Distance = 10 * 6

Distance = 60m

Hence LM = 60m

Since LN = LM + MN

160 = 60 + MN

MN = 160-60

MN = 100m

If the object moves from M to N at an average speed of 25 m/s througj a distance od 100m, the time taken will be expressed as;

Time = distance/speed

Time = 100/25

Time = 4secs

Total time taken to move from L to N is 6secs + 4secs = 10secs

The average speed of the object for it's entire journey from L to N will be:

Average speed = Distance LN/10

Average speed for the entire journey = 160/10 = 16m/s

Hence the average speed of the object for it's entire journey from L to N is 16m/s

for ex: the reciprocal of 3/4 is 4/3. it is the opposite.

reciprocal definition:

a mathematical expression or function so related to another that their product is one; the quantity obtained by dividing the number one by a given quantity.

sorry, i can't understand your question. will later if you describe more clearly!

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