The positions of two airplanes approaching an airport are plotted in a coordinate plane with the airport located at (0,0). The locations of the planes are given by the coordinates (7, 2) and (-1, -8). Each grid square is 1 mile wide. How far apart are the approaching airplanes? Round your answer to the
nearest tenth of a mile.

  12.8 miles

Step-by-step explanation:

The distance is given by the distance formula:

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  d = √((-1 -7)^2 +(-8-2)^2) = √((-8)^2 +(-10)^2) = √(64 +100)

  d = √164 ≈ 12.8

The planes are about 12.8 miles apart.

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answer: d.) the total number of protons and neutrons is 15

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i believe that the answer is

b. y-1=-2(x-4)

hope this !