A) Solve the Gompertz equation dy dt = ryln(K/y)
subject to the initial condition y(0) = y0.
B) For the given data r = 0.73 per year, K = 80,300 kg, and y0 K = 0.25. Use the Gompertz model to find the predicted value of y(4).
C) For the same data as in part (b), use the Gompertz model to find the time τ at which y(τ) = 0.77K.

Acourgette seed and a pumpkin seed is planted p(courgette seed germinates) 4/5 and p(pumpkin seed germinates) = 1/6 what is the probability that both seds germinate

Solve the equation x/4 - 5= -8 -27 -12 -7 12

The annual snowfall in a town has a mean of 38 inches and a standard deviation of 10 inches. last year there were 63 inches of snow. find the number of standard deviations from the mean that is, rounded to two decimal places. 0.44 standard deviations below the mean 2.50 standard deviations below the mean 0.44 standard deviations above the mean 2.50 standard deviations above the mean