Determine the slope of line (AB) and the slope of line (CD). Determine whether line (AB) and line (CD) are parallel, perpendicular, or just intersecting (neither). Points A and B line on the line y = 2/3x + 4. Points C and D line on the line 6x + 4y = 16.

The slopes are perpendicular

Step-by-step explanation:

Points A and B line on the line y = 2/3x + 4.

This line is in the form

y = mx+b where m is the slope

The slope is 2/3

Points C and D line on the line 6x + 4y = 16.

Solve for y

6x+4y = 16

4y = -6x +16

Divide by 4

4y/4 = -6/4x + 16/4

y = -3/2 x +4

The slope is -3/2

The slopes multiply to -1

2/3 * -3/2 = -1

so they are perpendicular

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

"exterior angles = 360 / number of sides.

60 = 360 / sides

sides = 360 / 60

sides = 6"