A model rocket is launched upward at a speed of 96 feet per second from a platform 7 feet above the ground. The path of the rocket can be modeled by the projectile equation, h(t)=-16t^2+v₀t+h₀
1. What is the maximum height the rocket will reach?
2. What is the average rate of change from the initial height to the maximum height?

151 ft

48 ft/s

Step-by-step explanation:

h(t)=-16t^2+v₀t+h₀

v₀ = 96  and

h₀ = 7

h(t)=-16t^2+96t+7

The maximum height is at the vertex

The x values of the vertex is at

x = -b/2a = -96/ (2*-16) = -96/-32 =3

Substitute this into the function to find the maximum height

h(3) = -16 ( 3)^2 +96*3+7

    -16*9 +288+7

     151

The maximum height is 151 ft

Average rate of change from 0 to 3

h(3) - h(0)

3-0

151 -7

3

144/3

48ft/s

not only in mathematics, scientific proof also are required in the other field of science. also maths proofs are of particular structure, containing steps and logics. so proving is like doing science, it is science. that's why it is important to prove. 

an inaccurate proof leads to errors, or stating results that are not accurate.  which wil mess the probelm up you dont want this