If g(x)=k•f(x), what is the value of k

step 1

find the equation of f(x)

points

(2,1)  and (0,-3)

m=(y2-y1)/(x2-x1)> m=(-3-1)/(0-2)> m=2

y-y1=m(x-x1)> y+3=2*(x-0)> y=2x-3

f(x)=2x-3

step 2

find the equation of g(x)

points

(0,6)  and (2,-2)

m=(y2-y1)/(x2-x1)> m=(-2-6)/(2-0)> m=-4

y-y1=m(x-x1)> y-6=-4*(x-0)> y=-4x+6

g(x)=-4x+6

step 3

find the value of k

If g(x) = k* f(x)

so

-4x+6=k*[2x-3]> -4x+6=2kx-3k

-4x=2kx> k=-2

6=-3k> k=-2

the answer is

k=-2

Step-by-step explanation:

not my answer btw :)

answer: about 22.67

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c