A bag has 5 yellow marbles, 3 red marbles and 2 blue marbles. Quinn randomly picks a marble from the bag and returns it before another is picked. How many times would Quinn expect to pick a blue marble if he picks a marble 200 times?

Quinn can expect to pick blue 40 times

Step-by-step explanation:

the probability of picking blue is stated as 2/10 which can be reduced to 1/5

multiply the number of times they pick a marble ( shown as 200) by the probability of picking a blue one ( 1/5)

200 x 1/5 = 200 / 5 = 40

Quinn can expect to pick blue 40 times

40 blue marbles

Step-by-step explanation:

First find the probability of a blue marble

P (blue) = number of blue marbles / total marbles

            = 2 blue/ ( 5+3+2) total

             = 2/10

              =1/5

We can use this since we return the marble to the bag each time

We multiply this by 200 for the number of times it is picked

200 * 1/5 = 40

We should expect to pick 40 blue marbles

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

vbbv

step-by-step explanation: