Find the equation of the line parallel to -5x+2y=12 and through (10,21)

y=5/2x-4

Step-by-step explanation:

im pretty sure

y= 2.5x -4

Step-by-step explanation:

1. Rearrange the equation so that it is in the form y = mx + c.

Add 5x to both sides:

-5x + 5x + 2y= 12 + 5x

2y= 5x + 12

Divide both sides by two:

2y/2= 5x/2 + 12/2

y= 2.5x + 6

2. Find the gradient of the line.

The gradient of the line is the coefficient (the number in front of) x.

For this line, it would be 2.5. (y= 2.5x + 6)

3. Start an equation for the parallel line.

Parallel lines have the same gradients.

This means that we know that the equation we are looking for will be:

y= 2.5x + c

4. Substitute in the values of x and y we have been given.

Coordinates come in the form (x, y), which means we know the values of x and y for one point. So, when x= 10, y=21.

We can substitute these into the equation we have started.

21= 2.5 x 10 + c

21= 25 + c

5. Solve for c.

Subtract 25 from both sides of the equation:

21- 25= 25- 25 + c

-4= c

6. Form the final equation.

The equation of the line parallel to -5x+2y=12 that passes through (10, 21) is:

y= 2.5x -4

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6