Which shows the linear equation −23x = 10y – 2 written in standard form? A)
x+15y=3

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B)
−23x=10y−2

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C)
30y=−2x+6

cross out

D)
2x−30y=6

multiply each one by 3.14

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen