In the diagram to the left, if m∠aed=152° , find each angle measure

Step-by-step explanation:

1). ∠1 and ∠2 are supplementary.

  m∠1 + m∠2 = 180°

2). ∠1 and ∠2 are complementary angles.

   m∠1 + m∠2 = 90°

3). If ∠1 and ∠2 are vertical angles,

   m∠1 = m∠2 = 64°

4). ∠Q and ∠R are complementary angles.

   m∠Q + m∠R = 90°

   If m∠R = 73°,

   m∠Q + 73° = 90°

   m∠Q = 90° - 73°= 17°

5). m∠AED = 135°

a). Since, ∠AED and ∠AEC are supplementary angles,

   m∠AED + m∠AEC = 180°

   m∠AED = 152°

   152° + m∠AEC = 180°

   m∠AEC = 180° - 152° = 28°

b). m∠CEB + m∠AEC = 180°

    28° + m∠CEB = 180°

    m∠CEB = 180° - 28° = 152°

c). m∠FEC = m∠FEA + m∠AEC

                 = 90° + 28°

                 = 118°          

the answer will be b x² +x-1

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.