A symphony orchestra is arranged in a semicircle around the conductor. The rows are about 3 feet apart, with the first row about 6 feet from the conductor. A mid-sized orchestra has about 6 rows of chairs. What is the approximate delay between the instant when a play at the 6th row start a note and when the conductor hears the note?

19 ms

Step-by-step explanation:

We need to find the time it takes for the sound from the 6th row gets to the conductor.

Since there are 6 rows and each row is 3 feet apart, since the orchestra is arranged in a semi-circular manner around the conductor, the distance from the 6 th row to the 1st row is (6 - 1) × 3 = 5 × 3 = 15 feet.

Now, since the conductor is 6 feet from the first row, his distance from the 6th row is 15 feet + 6 feet = 21 feet.

So, time approximate delay between the instant when a play at the 6th row start a note and when the conductor hears the note, t = distance between 6th row and conductor/speed of sound.

Speed of sound = 343 m/s

distance between 6th row and conductor = 21 feet. In meters, it is 21 × 0.3048 m = 6.4008 m

t = 6.4008 m ÷ 343 m/s

= 0.019 s

= 19 ms

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !

step-by-step explanation:

in which figure is point g a centroid