Factor the trinomial x²-11x+30?

(x-5)(x-6)

Step-by-step explanation:

when we look at something like this we have a, b, and c

a=1 (in front of x)

b=-11

c=30

our goal is trying to find factors of c that will give us b so in this case factors of 30 that will give us -11

so when you list all the factors of 30 you find that 6 and 5 both equal 30 when multiplied and add up to 11

but... we need -11 so if we change the signs both to negative that will give us a -11 when added and also a positive 30 when multiplied (-6)(-5)

so we then write it as (x-6)(x-5)

and if you FOIL that out you will end up getting the original equation :)

hope this helps!

i can't read the graph

step-by-step explanation:

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8