How do you prove each of the following properties of a parallelogram? -Opposite sides of a parallelogram are congruent.

-Opposite angles of a parallelogram are congruent.

-The diagonals of a parallelogram bisect each other.

-If the diagonals of a quadrilateral bisect each other, then the quadrilateral is a parallelogram.

-Rectangles are special parallelograms with congruent diagonals.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

1.3 million hoops i believe

answer: no

step-by-step explanation: because the big angle will spread away the 2 side that it is on and make the opposite side even longer.