Dan’s school is planning a field trip to an art museum. Bus company A charges a $60 rental fee plus $4 per student Bus company B charges $150 plus $2 per student. How many students would have to go for the cost to be the same?

45 students

Step-by-step explanation:

Company A’s charge can be represented by: 4s+60

Company B’s charge can be represented by: 2s+150

s is the charge per student

To find the cost at which they are the same, I will set both equations equal to each other.

4s+60=2s+150

-2s -2s

2s+60=150

-60 -60

2s=90 Divide both sides by 2

s=45

So when 45 students are going, the cost for both companies are the same.