4. Paul and Frank are on the same bike path 39.15 miles apart. The are going to ride their bikes toward each other until they meet. Frank starts pedaling 13 hours before Paul.
Paul rides 1.8 miles per hour faster than Frank. If they meet three hours after Paul
starts riding, find the speed of each biker.

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.