What is the approximate ratio of the diameter of the Sun to the diameter of Mars?
A. 5 x 10^-3
B. 5 x 10^2
C. 2 x 10^2
D. 2 x 10^3

not sure how to help because there is no photo

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°