The area of a rectangular wall of barn is 160 square feet. its length is 4 feet longer than twice its width. find the width of the wall of the barn

8 feet

Step-by-step explanation:

Given: the area of a rectangular wall of barn is 160 square feet. its length is 4 feet longer than twice its width.

To Find:  the width of the wall of the barn

Solution:

Area of rectangular wall of barn

Let the length of wall of barn is

Let the width of wall of barn is

now,

length of wall of barn is,

Area of wall of barn

on factorizing

 as width cannot be less than zero,

Width of the wall of barn is  

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

a

step-by-step explanation: