A heavy lift rocket has an empty mass of about 4.8 x 104 kg. After it is fueled, it has a mass of 6.1 x 10 kg. What is the mass of fuel that was added? (1 point)
O 1.3 x 105 kg
O 5.62 x 10 kg
O 1.3 x 104 kg
O 5.62 x 105 kg

c

Step-by-step explanation:

The rocket better weigh more after it is fueled. So the weight must be 6.1*10^4 after fueling.

6.1 * 10^4 - 4.8*10^4

The easiest way to do this is to take it out of scientific notation.

61000 - 48000 = 13000 kg

If you insist on scientific notation, it is 6.1*10^4 - 4.8*10^4 = 1.3 * 10^4 which makes the answer C

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204