Find the equation of the line through point (3,2) and perpendicular to 3x + 5y = 15

y=5/3x-3

Step-by-step explanation:

first, let's put 3x+5y=15 into y=mx+b form

move 3x to the other side

5y=-3x+15

divide by 5

y=-3/5x+3

now, perendicular lines have slopes that are negative and reciprocal.

With our new equation we can automatically find the slope, which would be 5/3.

now, we need to find b

plug the points (3,2) into y=5/3x+b

2=5/3(3)+b

2=5+b

-3=b

so that means that our equation will now be

y=5/3x-3.

Hope this helps!

6e14 is the answer.