What is the inverse of f(x) =1/3x+2?

f-1 (the -1 is the power of f') (x)=3x-6

Step-by-step explanation:

f (x) = 1/3x+2 use substitution

y = 1/3x +2 Interchange the variables

x = 1/3y +2 swap the sides

1/3y +2 = x multiply both sides

y + 6 =3x Move the constant to the right

y = 3x - 6 Use substitution

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option