Maria drew two parallel lines KL and MN intersected by a transversal PQ, as shown below: Two parallel lines KL and MN with PQ as a transversal intersecting KL at point R and MN at point S. Angle KRS is shown congruen Which theorem could Maria use to show the measure of angle KRQ is equal to the measure of angle PSN? (1 point) Alternate Exterior Angles Theorem Alternate Interior Angles Theorem Same-Side Interior Angles Theorem Vertical Angles Theorem

i think asking google will you get the answer to that question

x-150=475   x=625

step-by-step explanation:

if the bike after the sale ($150) is $475 then just simply add 150 to 475.

is there supposed to be a picture here?

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft