HAY IN THE MIDDLE OF THE BARN: There are one thousand and forty-one bales of hay in the barn. Farmer John is getting ready for Fall Festival at the Farm to spread it out for social distancing, so he got up this morning and stacked more bales in the barn today. There are now two thousand three hundred and fifty-eight bales of hay in the barn. How many bales did he store in the barn. (a) Write an equation for the scenario (b) Solve the equation and state your answer in a complete sentence.

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Step-by-step explanation:

Given that:

Initial number of bales of hay = 1041 bales

After stacking more bales in the barn:

Total number of bales after stacking = 2,358 bales

Equation for scenario b

Initial bales + added bales = total number of bales after stacking

Let added bales = b

1,041 + b = 2,357

Added bales = Newly stacked bales:

1041 + b = 2,357

b = 2357 - 1041

b = 1,316

The stacked bales of hay stacked to join the initial is. 1,316 bales

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

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