Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution set of this problem? (negative infinity, negative 21) (negative infinity, negative 21 right-bracket Left-bracket negative 21, positive infinity) (21, positive infinity)

b. (- infinity, - 21]

Step-by-step explanation:

Let x be the unknown number. Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.

5 × (x + 27) ≥ 6 × (x + 26)

We apply the distributive property.

5x + 135 ≥ 6x + 156

135 - 156 ≥ 6x - 5x

-21 ≥ x

x is less than or equal to -21. The solution set of this problem is

(- infinity, - 21].

answer would be 8.64 or s = 11π/4 inches

step-by-step explanation:

s = r θ  

where s = arc length  

r = radius = 3 inches  

θ = central angle in radians = ( π /180)*165  

s = 3(π/180)*165  

= 8.64 inches

do it yourself this is easy

step-by-step explanation: