Professor Cramer determines a final grade based on attendance, two papers, three major tests, and a final exam. Each of these activities has a total of 100 possible points. However, the activities carry different weights. Attendance is worth 3%, each paper is worth 9%, each test is worth 17%, and the final is worth 28%. (a) What is the average for a student with 81 on attendance, 90 on the first paper, 92 on the second paper, 86 on test 1, 71 on test 2, 93 on test 3, and 62 on the final exam

78.67

Step-by-step explanation:

The computation of the average for a student is shown below:

= Different Weights × different activities

= (3% × 81) + (9% × 90) + (9% × 92) + (17% × 86) + (17% × 71) + (17% × 93) + (28% × 62)

= 2.43 + 8.1 + 8.28 + 14.62 + 12.07 + 15.81 + 17.36

= 78.67

Hence, the average of the student is 78.67

We simply applied the above formula

7.3

step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94