The Hawaiian language has 12 letters: five vowels and seven consonants. Each of the 12 Hawaiian letters are written on a slip of paper and placed in the bag. A letter is randomly chosen from the bag and then replaced. Then, a second letter is randomly chosen from the bag. What is the probability that two vowels are chosen?

StartFraction 5 Over 72 EndFraction

StartFraction 25 Over 144 EndFraction

StartFraction 7 Over 12 EndFraction

Five-sixths

Step-by-step explanation:

Given: The Hawaiian language has 12 letters: five vowels and seven consonants. A letter is randomly chosen from the bag and then replaced. Then, a second letter is randomly chosen from the bag.

To find: probability that two vowels are chosen

Solution:

Probability that a vowel is chosen = number of favourable outcomes/ Total number of outcomes

If a letter is randomly chosen from the bag and then replaced and then, a second letter is randomly chosen from the bag,

Probability that two vowels are chosen = probability that the first letter is a vowel × probability that the second letter is a vowel such that first letter is  replaced

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.