A poll shows that 50% of students play sports A random sample of 20 students showed that

70% of them play sports

A number generator was used to simulate 20

samples from a population in which 50% of

students play sports. The results are shown in

the dot plot

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0.1 0.2 03 04 05 06 07 08 0.9

1

What is the chance of getting a sample

proportion of 70% or greater?

0

0.2

03

The chance of getting a sample  proportion of 70% or greater is 0.026.

Step-by-step explanation:

We are given that a poll shows that 50% of students play sports .

A random sample of 20 students showed that  70% of them play sports.

Let = sample proportion of students who play sports

The z-score probability distribution for the sample proportion is given by;

                           Z  =    ~ N(0,1)

where, = sample proportion of students who play sports = 70%

           p = population proportion of students who play sports = 50%

           n = sample of students = 20

Now, the chance of getting a sample  proportion of 70% or greater is given by = P( 70%)

   P( 70%) = P( ) = P(Z 1.95) = 1 - P(Z < 1.95)

                                                                 = 1 - 0.97441 = 0.026

The above probability is calculated by looking at the value of x = 1.95 in the z-table which has an area of 0.97441.

Hence, the chance of getting a sample  proportion of 70% or greater is 0.026.

yeah and the opposite of cheating is studying ( you should try it some time)

step-by-step explanation:

i dont know

step-by-step explanation: