Find the HCF of 20,55,90
Pls help it is urgent if i dont get this answer i will fail

Step-by-step explanation:

Factors of 20 = 1 2 4 5 10 20

Factors of 55 = 1 5 11 55

Factors of 90 = 1 2 3 5 6 9 10 15 18 30 45 90

Hcf = 5

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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