If p(x)=2(x^2+1)+16, what is the value of p(12)?

Step-by-step explanation:

Hey there!

Given;

p(x)= 2(x^2+1)+16

And p(x)= 12

Now,

Putting value of p(12) in p(x)= 2(x^2+1)+16.

Therefore p(12)= 306.

Hope it helps...

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation:

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value