ata were collected on the amount spent by customers for lunch at a major Houston restaurant. These data are contained in the file Houston. Based upon past studies the population standard deviation is known with . Click on the datafile logo to reference the data. Round your answers to two decimal places. Use the critical value with three decimal places. a. At confidence, what is the margin of error? b. Develop a confidence interval estimate of the mean amount spent for lunch. to

The sample  is calculated by adding the samples and dividing by the number of sample size.

X ± 2.58(6$)/√64

Step-by-step explanation:

Given:

Data were collected  by 64 customers for lunch.

Based on past studies, the population standard deviation is known with =∂= $6

a)At 99% confidence

By using given information,

∂= $6, n= 64,

At 99% confidence, the value of z = 2.58

By using formula of margin error:

ME=za/2 ∂/√n

       = 2.58 $6/√64

        = 15.48/8

       =1.935

b)Find the 99% confidence interval for mean amount spent on lunch?

By using given information:

∂= $6, n= 64,

At 99% confidence, the value of z = 2.58

By using the formula:

X ± z∂/√n

Where x is the sample means, z is the %99 confidence level, which is equal to 2.58

The sample  is calculated by adding the samples and dividing by the number of sample size.

X ± 2.58(6$)/√64

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,