A stadium has 49,000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,053,500 from each sold-out event. How many seats does each section hold?

Step-by-step explanation:

Suppose the number of seats in Section A is x, the number of seats in Section B is y, the number of seats in Section C is z.          

1. The cost of all seats in Section A if each of it sells $25 is 25x.

   The cost of all seats in Section B if each of it sells $20 is 20y.

   The cost of all seats in Section C if each of it sells $15 is 15c.

   Suppose the stadium takes in $1,053,500 from each sold-out event, so we have:

25x   20y   15c = 1,053,500 (1)

2.  The number of seats in Section A equals the total number of seats in Sections B and C, so we have:

x = y   z

x - y -z = 0 (2)

3. According to the prompt, a stadium has 49000 seats, so we have:

x   y   z = 49000 (3)

(1),(2), and (3) -> You have to solve the set of three equations.

Then we will have: x = 24500  

                                 y = 14700

                                z = 9800

Therefore, in section A, a stadium has 24500 seats.

                  in section B, a stadium has 14700 seats.

                  in section C, a stadium has 9800 seats.

Hope my answer can help you.

answer: x=3 and y=4

step-by-step explanation: