Whatfour consecutive integers have a sum of 90

N + (n+1) + (n+2) + (n+3) = 90
if n is the first number, then the next number is 1 more than n, the next number is 2 more than n, etc.
Simplify the above expression:
4n + 6 = 90
4n = 84
n = 21
n+1= 22
n+2 = 23
n+3 = 24

The final answer is 3x3+6x2+8x+24+47x−2mark me brainliest