The amount of money raised during a competing fund-raising campaign is modeled by the function M defined by M(t)=240(2t−1)(2t+36), where M(t) is measured in United States dollars and t is the time in days since that campaign began. According to this model, is there a time t, for 0≤t≤2, at which the amount of money raised is 10 dollars? Justify your answer.

Step-by-step explanation:

If the amount of money raised during a competing fund-raising campaign is modeled by the function M defined by M(t)=240(2t−1)(2t+36), where M(t) is measured in United States dollars and t is the time in days, to get the time t if the money raised is 10 dollars, we will substitute M = 10 into the modeled function and calculate the value of t

M(t)=240(2t−1)(2t+36)

10=240(2t−1)(2t+36)

1 = 24(2t−1)(2t+36)

open the parenthesis

1 = 24(4t²+72t-2t-36)

1 = 96t²+1680t-864

96t²+1680t-865 = 0

On factorizing, t = 2 is not a factor of the expression. Hence there is not a time within the interval 0≤t≤2, at which the amount of money raised is 10 dollars

d. is the correct answer

step-by-step explanation:

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.