An oak tree is 60cm tall. it grows at a rate of 8% per year. a conifer is 50cm tall. it grows at a rate of 15% per year. how many years does it take before the conifer is taller than the oak?
in advance : )

I mite be incerect but i think it would be 2.7

Height=height at first(1+rate)^n
n=years

The height of this oak will be:
Data:
height at first=60 cm
rate=8%=8/100=0.08

height=60(1+0.08)^n=60(1.08)^n

The height of this conifer will be:
Data:
height at first=50 cm
rate=15%=15/100=0.15

height=50(1+0.15)^n=50(1.15)^n

The heights of both trees will be the same at n years, therefore:
60(1.08)^n=50(1.15)^n

Now, we can solve this logarithmic equation.
Ln[60(1.08)^n]=Ln[50(1.15)^n]
Ln 60+n*Ln 1.08=Ln 50+n*Ln 1.15
n*ln 1.08-n*Ln 1.15=Ln 50-Ln 60
n(ln 1.08-ln 1.15)=Ln 50-Ln 60
n=(Ln 50 - Ln 60) / (Ln1.08 - Ln 1.15)
n=2.90316784...≈2.9

2.9 years. 

Answers: the graph is translated down 1 unit and the domain and range of g(x) is the same as the domain and range of f(x).