![14x + 12] = 0\\\\14x+12=0\\\mathrm{Subtract\:}12\mathrm{\:from\:both\:sides}\\14x+12-12=0-12\\\\Simplify\\14x=-12\\\\\mathrm{Divide\:both\:sides\:by\:}14\\\frac{14x}{14}=\frac{-12}{14}\\\\Simplify\\x=-\frac{6}{7}](/tpl/images/0789/4923/fd449.png)
How many solutions does the following equation have?
14x + 12] = 0...
Mathematics, 05.10.2020 15:01 adrielalvarez267
How many solutions does the following equation have?
14x + 12] = 0
Answers: 3
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