The length of a rectangle is eight more than twice its width. The perimeter is 88 feet. Find the dimensions of the rectangle. A w = 10 ft, l = 18 ft

B w = 16 ft, l = 28 ft

C w = 18ft, l = 24 ft

D w = 12 ft, l = 32 ft

D w = 12ft, l = 32ft

Explanation:

Make an equation for your length based on the given information.

l = 2w + 8

Make an equation using what you know about the perimeter

p =2l + 2w, p = 88

88 = 2l +2w

Substitute in your previous equation for l.

88 = 2(2w + 8) + 2w

Distribute and simplify.

88 = 4w + 16 + 2w

88 = 6w + 16

72 = 6w

w = 12

Now you can solve for l using the first equation.

l = 2(12) + 8

l = 32

Your answer is w = 12fr, l = 32ft. You can check your work by plugging the values back into the perimeter equation.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)