The perimeter of a rectangle is 158 meters. The length is 7 more than the twice the width. Wrote and solve the system to determine the measure of the length and width of the rectangle

36 and 43

Step-by-step explanation:

let, length be (x+7) and width be x.

here,

perimeter of rectangle=2(l*w)

or,158=2(x+7*x)

or,158=4x+14

or,158-14=4x

or,144=4x

or,144÷4=x

x=36

width=36

length=x+7

=36+7

=43

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step-by-step explanation:

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