4. The student council sold flowers for the Sweetheart dance as a fundraising project. They sold 200 flowers that included carnations, roses, and Gerber
daisies. The carnations sold for $1.50 each, the roses sold for $3.75 each, and
the daisies sold for $2.25. Most of the order was carnations and there were
20 fewer roses than daisies. The total flower sales came to $453.00. How
many of each type of flower were ordered and sold.

Kindly check explanation

Step-by-step explanation:

Given that :

Total flowers sold = 200

Flowers are :

Carnations, Roses, and Gerber daisies

Carnations = c

Roses = r

Daisies = d

20 fewer roses than daisies ; r = d - 20

Total sales = $453

c = $1.50 each ; r = 3.75 each ; d = 2.25 each

c + d + d - 20 = 200

c + 2d = 220 - - (1)

1.50c + (d - 20)(3.75) + 2.25d = 453

1.50c + 3.75d - 75 + 2.25d = 453

1.50c + 6d = 528 - - - (2)

From (1)

c = 220 - 2d

1.5(220 - 2d) + 6d = 528

330 - 3d + 6d = 528

330 + 3d = 528

3d = 528 - 330

d = 198/3

d = 66

66 × 2.25 = $148.5

c = 220 - 2(66)

c = 88

88 * 1.50 = $132

r = d - 20

r = 66 - 20

r = 46

46 × $3.75 = $172.5

because they could drop even lower..

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.