For the function f(x)=x^{3}+2f(x)=x
3
+2, find f^{-1}(x)f
−1
(x).

In order to find for any function f(x), we must apply the 'transformation' y=x. In order to do that, we must define x in terms of y, i.e.., find f(y), then set y=x. Let y=f(x) y=(x-3)^3+1 y-1=(x-3)^3 x-3=root(3)(y-1) x=3+root(3)(y-1) We've now found f(y), so we must set y=x by replacing x with y and y with x. f^-1(x)=y=3+root(3)(x-1)

answer: f true

step-by-step explanation: