The number of emails that Dave receives each day at his actuarial job has a Poisson distribution with mean 2 during each weekday and mean 1 each day during the weekend. The number of emails that Dave receives on one day is independent of the number of emails that he receives on the other days. Dave does not receive any personal emails. If today is Thursday, what is the probability that Dave receives his first email two days later, on Saturday

answer: idk

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the answer i believe is 27 units.

step-by-step explanation:

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