Look at the digit to the right. if the digit to the right is less than 5, the digit in the roundig place stay the same. if the digit in the right is 5 or greater the digit in the rounding place increase by one. write zeros for the digits to the right of the rounding place. 389,422 209,767 191,306 66,098

i think its a and d

step-by-step explanation:

10 b/c 5*2 =10

step-by-step explanation:

the bolded word " farsighted" could be replaced with visionary.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: