Solve the equation 6=y-5 which step can you use to solve the equation 6+y-5

Drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. the heights of the girls in an advanced swimming course are 55, 60, 59, 52, 65, 66, 62, and 65 inches. match the measures of this data with their values.

For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]

10x − 5y + 14 = 0 whats the answer pls