Consider the function f(x) = round(x), which rounds the input, x, to the nearest integer. Is this function one-to-one? Explain or justify your answer.

The function f(x) = round(x) is not one - to - one since different input values of X could yield the same output.

For instance :

Given that x = 1.4

f(x) = round(x)

f(1.4) = round(1.4)

Output = 1 ( nearest integer)

Since, different input values of X could yield the same the output, then the function is not one - to - one.

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No, it's not a one-to-one function

Step-by-step explanation:

Given

Required

Determine if this function is one-to-one

I'll answer this question using the following illustrations;

Assume x = 4.6

would be

Also assume x = 4.8

would be

More generally;

Would result in:

Since, there's a always a possibility of f(x) having one value for various values of input x, then we can conclude that the function is not a one-to-one function

idk

step-by-step explanation:

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