In this activity, you will use Hubble’s law, v = H0d, and the definition of velocity, v=d/t, to calculate the approximate age of the universe, t. Consult the math review if you need help with scientific notation, exponents, or solving one-step equations. Part A
To find time, t, the age of the universe, you must first isolate the variable t. Rewrite the velocity equation v=d/t so that you are solving for time.

This question consists of 2 parts, a and b. marco got a quotient of 70 when he divided 49 by 0.07. part a what is the correct answer to this problem? part b what mistake did marco make? you!

6.(q^9)^2 a. 2q^18 b. q^18 c. q^81 d. q^11 7.(6q^6)^-4 a. 6q^1296 b. 1296q^2 c. 1/1296q^24 d. 6q^-24 8. what is the value of 12x^-3 y^-1 for x = -1 and y = 5? a. -12/5 b.-10 c.-0 d.5/12 9. (y^-5)^10y^10 a. y^-60 b. y^60 c. y^-150 d. y^150 find the simplified form of each expression. 10. (4/7^5)^2 a.8/14^10 b.16/49^25 c.16/49y^10 d.8/14y^25 11. determine if the number 3.43 times 10^-6 is written in scientific notation. if not, explain. a. yes; the number is written scientific notation. b. no; the first factor is not a number between 1 and 10. c. no; it is not written as a number times a power of 10

The highest point on earth is the peak of mount everest if you climb to the top you would be approximately 29,035 feet above sea level at remembering that amount is 5280 feet percentage of the height of the mountain would you have to climb to reach a point 2 miles above sea level