A grain silo is built from two right circular cones and a right circular cylinder with internal measurements represented by the figure if the density of com 48 pounds per cubic feet, what would be the weight of the com in a full silo? ASAP help!!

  50,265 lb

Step-by-step explanation:

The volume of each cone is ...

  V = (1/3)πr²h = (1/3)π(5 ft)²(5 ft) = 125π/3 ft³

The volume of the cylinder is ...

  V = πr²h = π(5 ft)²(10 ft) = 250π ft³

Then the volume of the bin is ...

  V = cylinder volume + 2 × cone volume = (250π +2(125π/3)) ft³

  V = 1000π/3 ft³

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Multiplying this volume by the density gives the weight of the corn.

  ρV = (48 lb/ft³)(1000π/3 ft³ = 16000π lb ≈ 50,265 lb

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)