Let f (x) = sqrt x and g (x) = 3x+2. find the range of (f. g) (x)

[0, infinity)

Step-by-step explanation:

Focus on f(x) = sqrt(x) first.  The domain of this function is [0, infinity), and the range is [0, infinity).

The product (f*g)(x) is sqrt(x)*(3x + 2).

This leads to the conclusion that the range of  (f.g) (x) is  identical to the range of sqrt(x), which is [0, infinity).

these sign is used to tell weather the number is greater or less than the number   <   or >     but this sign means its equal =    

hope this you and

step-by-step explanation:

where did you get them? if you picked from the grass, is is probably poisonous.

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