If f(x)=1/x+2 and g(x)=1/x-3 find (f-g)(x). assume all appropriate restrictions to the domain

-1

Step-by-step explanation:

(1/x+2)-(1/x-3)=f(x)-g(x)

2-3=-1

-1=f(x)-g(x)

(f-g)×(x)=-1

(maybe im not so sure tho)

two data sets with the same median will not have the same varaibility

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.