Question 4 (4 points) (02.07)
The figure shows two parallel lines AB and DE cut by the transversals AE and BD:
А
B
1
2
3
С
4
6
5
D
Which statement best explains the relationship between AABC and AEDC? (4 points)
Оа
AABC - AEDC because mz3 = m26 and mz1 = 24
Ob
AABC - AEDC because m23 = m_4 and m_1 = m_5
AABC = AEDC because m23 =m24 and m_1 = m_5
Od
AABC = AEDC because mx3 = m26 and 261 = m_4

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°