Two points A and B are on opposite sides of a building. A surveyor selects a third point C to place a transit. Point C is 52 feet from point A and 64 feet from point B. The angle ACB is 52°. How far apart are points A and B? Round to the 10th place.

Step-by-step explanation:1.

Use law of cosine.

AB^2 = AC^2 + BC^2 - 2 * AC * BC * cos(angle ACB)

AB^2 = 53^2 + 71^2 - 2(53)(71)cos(53)

Using calculator,

AB = about 57.6259 feet

2.

Law of cosine again.

d^2 = 400^2 + 90^2 - 2(400)(90)cos(45)

using calculator,

d = about 342.3278 feet

For range i think it’s area

First, think of what you know. you know that the number t the end of the equation will need to be subtracted because it is the money he lost from buying the lawn mower. and your first two weeks have negative profit, so that tells you that c and d are wrong. now you can plug any of the weeks into a and b to see which one works. i'll start with plugging week 1 into a.this isn't right because it says your answer for week one should be -90.so now we need to try the same thing with b.this one got you the right answer, (sometimes if you only check with one of the weeks multiple will work so you need to check with more of the weeks, but it worked out fine here)this means that b is the correct answer.let me know if you need more clarification. i hope this : )